If A=`[[cosalpha,sinalpha],[-sinalpha,cosalpha]]` then show that `A^2=[[cos2alpha,sin2alpha],[-sin2alpha,cos2alpha]]`

If A=[[cosalpha,sinalpha],[-sinalpha,cosalpha]] ,show that A^2=[[cos2alpha,sin2alpha],[-sin2alpha,cos2alpha]]

If A=[{:(cosalpha,sinalpha),(-sinalpha,cosalpha):}] , show that A^(2)=[{:(cos2alpha,sin2alpha),(-sin2alpha,cos2alpha) :}].

if A=[[cosalpha,sinalpha],[-sinalpha,cosalpha]] be such that A+A'=I then alpha

If A=[(cos alpha,sinalpha),(-sinalpha,cosalpha)] , verify that A'A=I_2

If A_(alpha)=[(cosalpha,-sinalpha),(sinalpha,cosalpha)] , then

If A=[[cosalpha, -sin alpha] , [sin alpha, cos alpha]] then A+A'=I then alpha=

If A=[[cosalpha, sin alpha] , [-sin alpha, cos alpha]] and A^(-1)=A' then alpha=

If A_(alpha)=[(cosalpha,sinalpha),(-sinalpha,cosalpha)] then (A_(alpha))^2=?

If A(alpha)=[{:(cosalpha,sinalpha),(-sinalpha,cosalpha):}] then prove that A(alpha)A(-alpha)=I .