गुणनखंड निकले :
`x^(2) + 2ax- b^(2) +2ab`

x^(2)+2ab=(2a+b)x

Factorise the using the identity a ^(2) + 2 ab + b ^(2) = (a + b) ^(2) a ^(2) x ^(2) + 2 ax +1

Factorise: x^(2)-ax-bx + ab

If the abscissae of points A, B are the roots of the equation x^(2) + 2ax -b^(2) =0 and ordinates of A, B are roots of y^(2) + 2py -q^(2) =0 , then find the equation of the circle for which AB is a diameter.

Factorise the using the identity a ^(2) + 2 ab + b ^(2) = (a + b) ^(2) a ^(2) x ^(2) + 6ax + 9

Factorise : (iv) ax^(2) + b^(2) y - ab^(2) - x^(2) y

If x+ 2 is a factor of x^(2) + ax + 2b and a+b = 4 then a = …………..

{:(ax - by = a^(2) + b^(2)),(x + y = 2a):}