If the f(x)`=(log(1+ax)-log(1-bx))/x`,
`xne0` is continuous at x = 0 then, f(0) = .....

f(x) = ( log (1 +ax ) - log (1 - bx))/(x) is continuous at x = 0 then f(0) =

If the function f(x)=(log(1+ax)-log(1-bx))/(x) is continuous at x=0, then f(0)=

f(x)={(log(1+2ax)-log(1-bx))/(x),x!=0x=0

Value of f(0) so that f(x) = (log(1+bx)-log(1-ax))/x is continuous at x = 0 is

if the function f(x) defined by f(x)=(log(1+ax)-log(1-bx))/(x), if x!=0 and k if x=0 is continuous at x=0, find k

If f(x)={((log(1+2ax)-log(1-bx))/(x)",", x ne 0),(k",", x =0):} is continuous at x = 0, then value of k is

If f(x) f(x) = (log{(1+x)^(1+x)}-x)/(x^(2)), x != 0 , is continuous at x = 0 , then : f(0) =

Find f(0) if the function defined as f(x) = {:{(log(1+x/a)-log(1-x/b))/x (for x ne 0) , is continuous at x = 0. ab ne 0

If f(x)={((1-cosx)/(x),xne0),(k, x=0):} is continuous at x=0 then k=