Three frineds A, B and C have some money. If A has `3//10` of the total money, B has `7//15` of the total money and C has `7//30` of the total money. Who has the biggest share of the money? If the total money is ₹ 1500, then how much money does A have ?

Explanation

To solve the problem step by step, let's break it down:

### Step 1: Understand the shares of A, B, and C
- A has \( \frac{3}{10} \) of the total money.
- B has \( \frac{7}{15} \) of the total money.
- C has \( \frac{7}{30} \) of the total money.

### Step 2: Find a common denominator
To compare the shares, we need to find a common denominator for the fractions. The denominators are 10, 15, and 30.

- The least common multiple (LCM) of 10, 15, and 30 is 30.

### Step 3: Convert each fraction to have the common denominator
- For A:
\[ \frac{3}{10} = \frac{3 \times 3}{10 \times 3} = \frac{9}{30} \]

- For B:
\[ \frac{7}{15} = \frac{7 \times 2}{15 \times 2} = \frac{14}{30} \]

- For C:
\[ \frac{7}{30} = \frac{7}{30} \quad (\text{remains the same}) \]

### Step 4: Compare the shares
Now we have:
- A: \( \frac{9}{30} \)
- B: \( \frac{14}{30} \)
- C: \( \frac{7}{30} \)

The largest numerator indicates the largest share:
- A: 9
- B: 14
- C: 7

B has the largest share.

### Step 5: Calculate how much money A has
The total money is ₹1500. To find out how much A has:
\[ \text{A's share} = \frac{9}{30} \times 1500 \]

### Step 6: Simplify the calculation
\[ \text{A's share} = 1500 \times \frac{9}{30} = 1500 \times 0.3 = 450 \]

### Conclusion
A has ₹450.

### Summary of Results
- B has the biggest share.
- A has ₹450.