The cost of the dozon oragnes is ₹ `43'1/1`. Find the cost of `2'1/3` dozen of oranges (in ₹).

Options

A. `203`
B. `203/2`
C. `101/2`
D. `100'1/2`

Explanation

To find the cost of \(2 \frac{1}{3}\) dozen oranges when the cost of one dozen oranges is \(43 \frac{1}{2}\) rupees, we will follow these steps:

### Step 1: Convert the mixed number to an improper fraction
The cost of one dozen oranges is given as \(43 \frac{1}{2}\). We can convert this mixed number into an improper fraction.

\[ 43 \frac{1}{2} = 43 + \frac{1}{2} = \frac{43 \times 2 + 1}{2} = \frac{86 + 1}{2} = \frac{87}{2} \]

### Step 2: Convert \(2 \frac{1}{3}\) dozen to an improper fraction
Next, we convert \(2 \frac{1}{3}\) dozen into an improper fraction.

\[ 2 \frac{1}{3} = 2 + \frac{1}{3} = \frac{2 \times 3 + 1}{3} = \frac{6 + 1}{3} = \frac{7}{3} \]

### Step 3: Calculate the cost of \(2 \frac{1}{3}\) dozen oranges
Now, we can find the cost of \(2 \frac{1}{3}\) dozen oranges by multiplying the cost of one dozen oranges by the number of dozens.

\[ \text{Cost} = \left(\frac{87}{2}\right) \times \left(\frac{7}{3}\right) \]

### Step 4: Multiply the fractions
To multiply the fractions, we multiply the numerators and the denominators.

\[ \text{Cost} = \frac{87 \times 7}{2 \times 3} = \frac{609}{6} \]

### Step 5: Simplify the fraction
Now, we simplify \(\frac{609}{6}\).

\[ \frac{609}{6} = 101.5 \]

### Final Answer
Thus, the cost of \(2 \frac{1}{3}\) dozen oranges is ₹ 101.5.

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