If x=2 and y=3, then find the values of
`(i) (2x+3y)/(4x-3y) " "(ii) (2x^(2)-7x+2y)/(2y^(2)-7y+2x)`

Answer

(i) `-13`
(ii) `0`

Explanation

x=2, y=3
`(i) (2x+3y)/(4x-3y)=(2xx2+3xx3)/(4xx2-3xx3)`
`=(4+9)/(8-9)=(13)/(-1)=-13`
`(ii) (2x^(2)-7x+2y)/(2y^(2)-7y+2x)=(2(2)^(2)-7(2)+2(3))/(2(3)^(2)-7(3)+2(2))`
`=(2xx4-14+6)/(2zxx9-21+4)=(8-8)/(18-17)=(0)/(1)=0`