A string fastened at both ends has successive resonances with wavelengths of 0.1 m for mth harmonic and 0.08 m for (m+1)th harmonic.
the length of the string is

A string fastened at both ends has successive resonances with wavelengths of 0.1 m for mth harmonic and 0.08 m for (m+1)th harmonic. The value of m is

A string fastened at both ends has successive resonances with wavelengths of 0.1 m for mth harmonic and 0.08 m for (m+1)th harmonic. The value of m is

A string fastened at both ends has successive resonances with wavelengths of 0.54 m for nth harmonic and 0.48 m for the (n+1) th harmonic and 0.48 m for the (n+1) th harmonic. (a) Which harmonics are these? (b) What is the length of the stirng? (c) What is the wavelength of the fundamental frequency?

A string fastened at both ends has successive resonances with wavelengths of 0.54 m for nth harmonic and 0.48 m for the (n+1) th harmonic and 0.48 m for the (n+1) th harmonic. (a) Which harmonics are these? (b) What is the length of the stirng? (c) What is the wavelength of the fundamental frequency?

A stretched string fixed at both end has n nods, then the lengths of the string is

The Equation for the vibration of a string fixed at both ends vibrating in its third harmonic is given by y = 2 sin (0.6x) cos (500 pi t) (x, y are in cm t is in sec). The length of the string is

A string of length 2m is fixed at two ends. It is in resonance with a tuning fork of frequency 240 Hz in its third harmonic. Then speed of wave sound in string and its fundamental frequency is:

A string of length 2m is fixed at two ends. It is in resonance with a tuning fork of frequency 240 Hz in its third harmonic. Then speed of wave sound in string and its fundamental frequency is:

The equation for the vibration of a string fixed at both ends vibrating in its third harmonic is given by y=2cm sin[(0.6cm^-1)x]cos[(500pis^-1)t] . The length of the string is