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In the figure, PS and QT are two straigh...

In the figure, PS and QT are two straight lines intersecting at the point R. PR = RQ. If `anglePRQ=98^(@) and angleTSR=40^(@)`, then find the angles of `angleT and angleQ`.

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The correct Answer is:
`42^(@), 41^(@)`

`angleTRS=anglePRQ=98^(@)` (vertically opposite angles)
In `DeltaTRS`,
`angleRTS=180^(@)-98^(@)-40^(@)`
`=180^(@)-138^(@)`
`=42^(@)`
In `DeltaPQR, angleRPQ=angleRQP" "("since"PR = QR)`
`=(180^(@)-98^(@))=(82^(@))/(4)=41^(@)`
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