A ball in the shape of rectangle is 16 feet long and 12 feet wide. How many tiles with 2 feet x 1 feet are rquired to cover the floor of the hall ?

Explanation

To solve the problem of how many tiles are required to cover the floor of a hall that is 16 feet long and 12 feet wide using tiles that are 2 feet by 1 foot, we can follow these steps:

### Step-by-Step Solution:

1. **Calculate the Area of the Hall:**
- The area of a rectangle is calculated using the formula:
\[ \text{Area} = \text{Length} \times \text{Width} \]
- Here, the length of the hall is 16 feet and the width is 12 feet.
- So, the area of the hall is:
\[ \text{Area} = 16 \, \text{feet} \times 12 \, \text{feet} = 192 \, \text{square feet} \]

2. **Calculate the Area of One Tile:**
- The area of a tile is calculated using the same formula:
\[ \text{Area} = \text{Length} \times \text{Width} \]
- The dimensions of the tile are 2 feet long and 1 foot wide.
- So, the area of one tile is:
\[ \text{Area} = 2 \, \text{feet} \times 1 \, \text{foot} = 2 \, \text{square feet} \]

3. **Determine the Number of Tiles Required:**
- To find the number of tiles required, divide the area of the hall by the area of one tile:
\[ \text{Number of Tiles} = \frac{\text{Area of Hall}}{\text{Area of One Tile}} = \frac{192 \, \text{square feet}}{2 \, \text{square feet}} = 96 \]

### Final Answer:
- Therefore, the number of tiles required to cover the entire floor of the hall is **96 tiles**.

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