If n=16 in plant cell, then how many bivalents in metaphase-I of meiosis are possible ?

Options

A. 32 bivalents
B. 16 tetravalents
C. 16 bivalents
D. 32 bivalents

Answer

To solve the problem of how many bivalents are possible in metaphase-I of meiosis when n=16 in a plant cell, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Value of n**:
- The variable n represents the haploid number of chromosomes. Given that n = 16, this means that the haploid set of chromosomes in the plant cell consists of 16 chromosomes.

2. **Determine the Diploid Number (2n)**:
- The diploid number of chromosomes (2n) is calculated by multiplying n by 2.
- Thus, 2n = 2 * 16 = 32.
- This means the plant cell has a total of 32 chromosomes.

3. **Understanding Bivalents Formation**:
- During meiosis, specifically in prophase-I, homologous chromosomes pair up to form structures called bivalents.
- Each bivalent consists of a pair of homologous chromosomes.

4. **Calculate the Number of Bivalents**:
- Since each bivalent is formed by pairing two homologous chromosomes, the total number of bivalents formed will be half of the total number of chromosomes in the diploid cell.
- Therefore, the number of bivalents = Total chromosomes / 2 = 32 / 2 = 16.

5. **Conclusion**:
- In metaphase-I of meiosis, when n = 16, the number of bivalents that can be formed is 16.

### Final Answer:
The number of bivalents in metaphase-I of meiosis is 16.

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