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If 256 is the third proportional of a an...

If 256 is the third proportional of a and b, where a:b = 3:16, then find the value of a +b.

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To solve the problem step by step, we can follow these instructions: ### Step 1: Understand the concept of third proportional If 256 is the third proportional of \( a \) and \( b \), it means that the ratio \( \frac{a}{b} \) is equal to \( \frac{b}{256} \). ### Step 2: Set up the ratio Given that \( a:b = 3:16 \), we can express this as: \[ \frac{a}{b} = \frac{3}{16} \] ### Step 3: Use the property of third proportional From the property of third proportional, we have: \[ \frac{a}{b} = \frac{b}{256} \] This can be rearranged to: \[ b^2 = 256a \] ### Step 4: Express \( a \) in terms of \( b \) From the ratio \( \frac{a}{b} = \frac{3}{16} \), we can express \( a \) as: \[ a = \frac{3}{16}b \] ### Step 5: Substitute \( a \) in the equation Now substitute \( a \) in the equation \( b^2 = 256a \): \[ b^2 = 256 \left(\frac{3}{16}b\right) \] This simplifies to: \[ b^2 = 256 \cdot \frac{3}{16} b \] ### Step 6: Simplify the equation Calculating \( 256 \cdot \frac{3}{16} \): \[ 256 \div 16 = 16 \quad \text{so} \quad 256 \cdot \frac{3}{16} = 48b \] Thus, we have: \[ b^2 = 48b \] ### Step 7: Rearrange the equation Rearranging gives us: \[ b^2 - 48b = 0 \] Factoring out \( b \): \[ b(b - 48) = 0 \] This gives us two solutions: \( b = 0 \) or \( b = 48 \). Since \( b \) cannot be zero, we have: \[ b = 48 \] ### Step 8: Find \( a \) Now substitute \( b = 48 \) back into the equation for \( a \): \[ a = \frac{3}{16} \times 48 \] Calculating this gives: \[ a = 9 \] ### Step 9: Find \( a + b \) Now, we can find \( a + b \): \[ a + b = 9 + 48 = 57 \] ### Final Answer Thus, the value of \( a + b \) is: \[ \boxed{57} \]
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