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Find the value of (-1)^(301)+(-1)^(302)+...

Find the value of `(-1)^(301)+(-1)^(302)+(-1)^(303)+.......+(-1)^(400)`.

A

1

B

101

C

100

D

0

Text Solution

Verified by Experts

The correct Answer is:
D
We know `(-1)^x`
`=-1`, when x is odd.
`=1` , when x is even.
`therefore (-1)^(301)+(-1)^(302)+....+(-1)^(400)`
`=(-1)+1+(-1)+1+...(100 " terms") =0`
Hence, the correct options is (d).
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