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Divide Rs 98 into two such that one part...

Divide Rs 98 into two such that one part of 6 times to the other part

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To solve the problem of dividing Rs 98 into two parts such that one part is 6 times the other part, we can follow these steps: ### Step-by-Step Solution: 1. **Define the Variables**: Let one part be \( x \). Then the other part will be \( 98 - x \). 2. **Set Up the Equation**: According to the problem, one part is 6 times the other part. Therefore, we can write the equation: \[ 98 - x = 6x \] 3. **Rearrange the Equation**: To solve for \( x \), we can rearrange the equation: \[ 98 = 6x + x \] This simplifies to: \[ 98 = 7x \] 4. **Solve for \( x \)**: Now, divide both sides by 7 to find \( x \): \[ x = \frac{98}{7} \] Calculating this gives: \[ x = 14 \] 5. **Find the Other Part**: Now that we have \( x \), we can find the other part: \[ 98 - x = 98 - 14 = 84 \] 6. **Conclusion**: The two parts are Rs 14 and Rs 84. To verify, we check if one part is indeed 6 times the other: \[ 84 = 6 \times 14 \] This is correct. ### Final Answer: The two parts are Rs 14 and Rs 84.
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PEARSON IIT JEE FOUNDATION-EQUATIONS AND THEIR APPLICATIONS-Short Answer type questions
  1. Divide Rs 98 into two such that one part of 6 times to the other part

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  2. One-third of a number is equal to 24, then find the value of 1(1)/(2) ...

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  3. The sum of three consectuve integers is 24. Find the smallest number

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  4. Solve, (x)/(3) + (x)/(6) + (x)/(9) = 11

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  5. Solve : 0.5y + 0.75y = 125

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  6. Solve : 2.5t + 7.3 t = 21.6 -t

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  7. Equal parts of a flag pole are painted with saffron, white, and green ...

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  8. A person covered 5//8 of his journey and he has to walk 240 m more to ...

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  9. A boy has given 7//12 of his marbles to his friend and is left with on...

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  10. A number is multiplied by 5 and 25 is subtracted from the product. The...

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  11. One-fouth of a certain number exceeds its one-seventh by 3. find the n...

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  12. Solve : (5x -2)/(3) + (4x+3)/(2) = (3x+19)/(2)

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  13. Solve : 0.3 (3y -4.5) + 2.9 (5.5 -5y) = 1

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  14. Solve : (9m+4)/(5) - (27 m + 1)/(8) - (1)/(2) = 0

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  15. Solve : 2m + 5 gt 9 - 4m, m in Q

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  16. Solve : (z)/(2) - (z)/(3) - (z)/(4) = -1

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  17. Solve : (y + 2)/(3) + (y + 3)/(2) = y + 1

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  18. Solve : (2n + 3)/(6n -5) = 1

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  19. Solve : 2(k + 3) + 3 (k-4) = 24

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  20. One-fifth of a number is 5 more than one-tenth of the number. Find the...

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