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Which of the following is a solution of `(2x -5)/(3) gt (3x + 3)/(4)` ?

A

`x = -5`

B

`x = -2`

C

`x = -29`

D

`x = -30`

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The correct Answer is:
To solve the inequality \(\frac{2x - 5}{3} > \frac{3x + 3}{4}\), we will follow these steps: ### Step 1: Eliminate the fractions To eliminate the fractions, we can multiply both sides of the inequality by the least common multiple (LCM) of the denominators, which is 12. \[ 12 \cdot \frac{2x - 5}{3} > 12 \cdot \frac{3x + 3}{4} \] ### Step 2: Simplify both sides Now we simplify both sides: \[ 4(2x - 5) > 3(3x + 3) \] Distributing on both sides gives: \[ 8x - 20 > 9x + 9 \] ### Step 3: Rearrange the inequality Next, we will rearrange the inequality to isolate \(x\). We can subtract \(9x\) from both sides: \[ 8x - 9x - 20 > 9 \] This simplifies to: \[ -x - 20 > 9 \] ### Step 4: Isolate \(x\) Now, we will add 20 to both sides: \[ -x > 9 + 20 \] This simplifies to: \[ -x > 29 \] ### Step 5: Multiply by -1 To solve for \(x\), we multiply both sides by -1. Remember that when we multiply or divide an inequality by a negative number, we must reverse the inequality sign: \[ x < -29 \] ### Conclusion The solution to the inequality is \(x < -29\). Now, we need to check which of the given options satisfies this inequality. The options are: - A) -5 - B) -2 - C) -29 - D) -30 Since we need \(x\) to be less than -29, the only option that satisfies this condition is: - D) -30

To solve the inequality \(\frac{2x - 5}{3} > \frac{3x + 3}{4}\), we will follow these steps: ### Step 1: Eliminate the fractions To eliminate the fractions, we can multiply both sides of the inequality by the least common multiple (LCM) of the denominators, which is 12. \[ 12 \cdot \frac{2x - 5}{3} > 12 \cdot \frac{3x + 3}{4} \] ...
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