Home
Class 8
MATHS
Find the smallest six-digit number which...

Find the smallest six-digit number which when divided by `15 and 6` leaves a remainder of `2` in each case.

Text Solution

Verified by Experts

The smallest six digit number is `100000`, the LCM of 15 and 6 is 30.
The smallest six digit number exactly divisible by 30 is `100020`.
`therefore` The required number is `10020 +2 =100022`.
Promotional Banner

Topper's Solved these Questions

  • REAL NUMBERS AND LCM AND HCF

    PEARSON IIT JEE FOUNDATION|Exercise Test your concepts very short type|30 Videos

  • REAL NUMBERS AND LCM AND HCF

    PEARSON IIT JEE FOUNDATION|Exercise Short answer type|15 Videos

  • RATIO, PROPORTION AND VARIATION

    PEARSON IIT JEE FOUNDATION|Exercise CONCEPT APPLICATION|60 Videos

  • SETS

    PEARSON IIT JEE FOUNDATION|Exercise CONCEPT APPLICATION (LEVEL 3) |8 Videos

Similar Questions

Explore conceptually related problems

Find the greatest four digit number which when divided by 18 and 12 leaves a remainder of 4 ineach case

Find the greatest four - digits number which when divided by 4,7 and 13 leaves a remainder 3 in each case.

The least number which when divided by 4,6,8,12 and 16 leaves a remainder of 2 in each case is :

Which is the least four-digit number which when divided by 5, 6 and 8 leaves remainder 2 in each case?

What is the lest number which, when divided by 5,6,8 and 10, leaves a remainder of 2 in each case?

What is the least number which, when divided by 5,6,8 and 10, leaves a remainder of 2 in each case?

Find the least number which when divided by 6,15 and 18 leave remainder 5 in each case.

Find the least three digit number which when divided by 20, 30, 40 and 50 leaves remainder 10 in each case.