Find the maximum possible length of the rope which can mesure 48 m and 36 m.
The following are the stpes involved in solving the above problem. Arrange them in the sequntila order.
(A) the greatest possible length is the HCF of 48 m and 36m.
(B) The HCF of 48 and 36 `=2^2xx3=12`.
(C) `48=2^4xx3,36=2^2xx3^2`.
(D) The greatest possible length of the rope `=12 m`.

Options

A. ABCD
B. ACBD
C. ADBC
D. BACD

Answer

B

Explanation

acbd is the required sequential order.