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If C=(5)/(9)(F-32), then express F in te...

If `C=(5)/(9)(F-32)`, then express F in terms of C.

A

`F=(9)/(5)C-32`

B

`F=32-(9)/(5)C`

C

`F=(9)/(5)(C+32)`

D

`F=(9)/(5)C+32`

Text Solution

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The correct Answer is:
To express \( F \) in terms of \( C \) from the equation \( C = \frac{5}{9}(F - 32) \), we can follow these steps: ### Step 1: Start with the given equation We have the equation: \[ C = \frac{5}{9}(F - 32) \] ### Step 2: Eliminate the fraction To eliminate the fraction, multiply both sides of the equation by 9: \[ 9C = 5(F - 32) \] ### Step 3: Distribute on the right side Now distribute the 5 on the right side: \[ 9C = 5F - 160 \] ### Step 4: Isolate \( F \) Next, we want to isolate \( F \). To do this, add 160 to both sides: \[ 9C + 160 = 5F \] ### Step 5: Solve for \( F \) Now, divide both sides by 5 to solve for \( F \): \[ F = \frac{9C + 160}{5} \] ### Final Result Thus, the expression for \( F \) in terms of \( C \) is: \[ F = \frac{9C}{5} + 32 \] ---

To express \( F \) in terms of \( C \) from the equation \( C = \frac{5}{9}(F - 32) \), we can follow these steps: ### Step 1: Start with the given equation We have the equation: \[ C = \frac{5}{9}(F - 32) \] ...
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PEARSON IIT JEE FOUNDATION-Formulae-Level 2
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  2. If H=(2b)/(a+b), then make b as the subject of the formula.

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  3. In (x)/(a)+(x)/(b)=1, make b as the subject of the formula.

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  4. The volume of a cone is V=(1)/(3)pir^(2)h. Make r as the subject of th...

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  5. In the formula V=(1)/(3)pr^(2)h, if V=9.42 units, h=4 units and pi=3.1...

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  10. Frame the formula: The square of the difference of p and q is equal to...

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  14. If S=(a)/(1-r^(3)), then expres r in terms of S and a.

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  15. In S=ut+(1)/(2)at^(2), S=96,t=8 and a=2, find u.

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  16. If C=(5)/(9)(F-32), then express F in terms of C.

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  17. If a=b-sqrt(b^(2)-1), express b in terms of a.

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  18. If (1)/(a)+(1)/(b)=(1)/(c)+(1)/(d), express a in terms of b,c and d.

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  19. If A=sqrt((s-a)(s-b)(s-c)), then express c in terms of A,s,a and b.

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