What number must be added to each term of the ratio 7:5 so that it becomes 4:3?

Answer

To solve the problem of what number must be added to each term of the ratio 7:5 so that it becomes 4:3, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Problem**: We need to find a number \( x \) that can be added to both terms of the ratio 7:5 to make it equal to the ratio 4:3.

2. **Set Up the Equation**: When we add \( x \) to both terms of the ratio, we can express this mathematically:
\[ \frac{7 + x}{5 + x} = \frac{4}{3} \]

3. **Cross-Multiply**: To eliminate the fraction, we can cross-multiply:
\[ 3(7 + x) = 4(5 + x) \]

4. **Expand Both Sides**: Distributing on both sides gives us:
\[ 21 + 3x = 20 + 4x \]

5. **Rearrange the Equation**: Now, we want to isolate \( x \). We can do this by moving all terms involving \( x \) to one side and constant terms to the other side:
\[ 21 - 20 = 4x - 3x \]
This simplifies to:
\[ 1 = x \]

6. **Conclusion**: The number that must be added to each term of the ratio 7:5 to make it 4:3 is:
\[ x = 1 \]

### Final Answer:
The number that must be added is **1**.

---