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if two numbers are in the ratio (1)/(15)...

if two numbers are in the ratio `(1)/(15):(1)/(20)`, then by what percentage is the second number less that the first? The following are the steps involved in solving the above problem. Arrange them in sequential order
(A) Difference between the two numbers is 4x-3x=x ltBrgt (B) Given that the ratio of two numbers
`=(1)/(15):(1)/(20)=20:15=4:3`
Let the numbers of 4x and 3x.
(C) The percentage by which the second number is less than the first number `=(x)/(4x)xx100%=25%`
(D) i.e., the second number is x less than the first number.

A

BADC

B

BDAC

C

DBAC

D

ABDC

Text Solution

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The correct Answer is:
A
(B),(A),(D) and (C) is the requried sequential order.
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