Is it possible to liquefy `CO_2` gas at `50^(@)` C ? Give a reason.

It is possible to liquefy a gas

Is is possible to liquefy a gas at any temperature?

The essential conditions for liquefaction of gases were discovered by Andrews in 1869 as a result of his study of pressure-volume-temperature relationship for CO_(2) . If was found that above a certain temperature, it was impossible to liquefy a gas whatever the pressure was applied. The temperature below which the gas can be liquefied by the application of pressure alone is called critical temperature (T_(c)) . The pressure required to liquefy a gas at this temperature is called the critical pressure (P_(c)) . The volume occupied by one mole of the substance at the critical temperature and pressure is called critcal volume. Critical constants are related with van der Waals' constant as follows: V_(c) = 3b, P_(c) = (a)/(27b^(2)), T_(c) = (8a)/(27 Rb) {:("Gases",A,B,C,D,),(P_(c) (atm),2.2,14,35,45,),(T_(c) (K),5.1,33,127,140,):} Which of the above gases cannot be liquefied at 100 K and 50 atm ?

The essential conditions for liquefaction of gases were discovered by Andrews in 1869 as a result of his study of pressure-volume-temperature relationship for CO_(2) . If was found that above a certain temperature, it was impossible to liquefy a gas whatever the pressure was applied. The temperature below which the gas can be liquefied by the application of pressure alone is called critical temperature (T_(c)) . The pressure required to liquefy a gas at this temperature is called the critical pressure (P_(c)) . The volume occupied by one mole of the substance at the critical temperature and pressure is called critcal volume. Critical constants are related with van der Waals' constant as follows: V_(c) = 3b, P_(c) = (a)/(27b^(2)), T_(c) = (8a)/(27 Rb) Gas A and can be liquefied at room temperature by applying pressure but gas B cannot. This reflects:

The essential conditions for liquefaction of gases were discovered by Andrews in 1869 as a result of his study of pressure-volume-temperature relationship for CO_(2) . If was found that above a certain temperature, it was impossible to liquefy a gas whatever the pressure was applied. The temperature below which the gas can be liquefied by the application of pressure alone is called critical temperature (T_(c)) . The pressure required to liquefy a gas at this temperature is called the critical pressure (P_(c)) . The volume occupied by one mole of the substance at the critical temperature and pressure is called critcal volume. Critical constants are related with van der Waals' constant as follows: V_(c) = 3b, P_(c) = (a)/(27b^(2)), T_(c) = (8a)/(27 Rb) The pressure required to liquefy a gas at the critical temperature is called :

One of the assumptions of kinetic theory of gases states that "there is no force of attraction between the molecules of a gas". How far is this statement correct ? Is it possible to liquefy an ideal gas ? Explain.

CO_(2) gas is liquefaction for 1 mole of CO_(2) . Then which statement is (are) correct in gaseous phase will (I) The maximum density of gas is 0.1 gm/ml (II) The density of liquid CO_(2) is 1 g/ml at 60 atm. (III) At point C 50% of CO_(2) is liquefied. (IV) The compressibility factor of gas at 27^(@)C is always less than 1. Which of the above is/are correct

Is photoelectric emission possible at all frequencies? Give reason for your answer?