An element X on treatment with oxygen gives Y which on hydrolysis produces Z.Z on treatment with higher oxide of carbon 'A' gives milky white precipitate 'B'. Identify X, Y, Z, A and B?

Explanation

As Z on treatment with oxide "A" of carbon gives milky appearance to the solution by forming. B, Z is `Ca(OH)_(2), A "is" CO_(2), B "is" CaCO_(3)`.
As Z is produved by hydrolysis of Y. Y is CaO. As Y is prepared by treating "X" with oxygen, X is Ca.
`underset(("X"))(Ca + O_(2)) rarr underset(("Y"))(CaO)`
`underset("Y")(CaO) + H_(2)O rarr underset("Z")(Ca(OH)_(2))`
`underset("Z")(Ca(OH)_(2)) + underset("A")(CO_(2)) rarr underset("B")(CaCO_(3)) + H_(2)O`