The reducing property of `SO_2` is shown in which of the following reactions

Options

A. `SO_2+H_2O+CL_2rarr2HCL+H_2SO_4`
B. `2H_2S +SO_2rarr2H_2O+3S`
C. `KOH +SO_2rarr K_2SO_3+H_2O`
D. None of the above

Explanation

To determine in which reaction sulfur dioxide (SO₂) shows its reducing property, we need to analyze the oxidation states of the elements involved in each reaction. A reducing agent is a substance that donates electrons and, in the process, gets oxidized itself, leading to a decrease in the oxidation state of another substance.

### Step-by-Step Solution:

1. **Identify the Reactions**: We have three reactions to analyze. We need to evaluate each one to see where SO₂ acts as a reducing agent.

2. **Understanding Oxidation States**: Recall that the oxidation state indicates the degree of oxidation of an atom in a compound. A decrease in oxidation state means that the atom is being reduced, while an increase means it is being oxidized.

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