A bike startingh from rest picks up velocity of 72 `km h^(-1)` over distance of 40m. Calculate its accleration

Explanation

Given `u=0`
`v=72km h^(-1)=72xx(5)/(18)=20 m s^(-1)`
`s=40 m`
using `v^(2)-u^(2)=2as`
`(20)^(2)-0=2axx40`
`a=(400)/(2xx40)=5 m s^(-2)`