Home
Class 8
PHYSICS
The physics teacher gave a rod of length...

The physics teacher gave a rod of length 'L' units to Roy and the teacher asked Roy to find the shift in the centre of gravity when `1//4` of the total length of the rod is removed. What will be the Roy's answer in terms of L?

Text Solution

Verified by Experts

Original length of rod = L units
`CG = (L)/(2)` units
New length of rod = `L - (L)/(4) = (3L)/(4)`
New position of `CG = (3L)/(8)`
Shift in `CG = (L)/(2) - (3L)/(8) = (4L - 3L)/(8) = (L)/(8)` units
Promotional Banner

Topper's Solved these Questions

  • DYNAMICS

    PEARSON IIT JEE FOUNDATION|Exercise EXAMPLE|11 Videos

  • DYNAMICS

    PEARSON IIT JEE FOUNDATION|Exercise TEST YOUR CONCEPTS(VERY SHORT ANSWER TYPE QUESTIONS)|31 Videos

  • DYNAMICS

    PEARSON IIT JEE FOUNDATION|Exercise Level 2|21 Videos

  • CHEMICAL EFFECTS OF ELECTRIC CURRENT

    PEARSON IIT JEE FOUNDATION|Exercise COMPETITION CORNER (MCQ)|48 Videos

  • ELECTRICITY

    PEARSON IIT JEE FOUNDATION|Exercise CONCEPT APPLICATION (Level 3)|10 Videos

Similar Questions

Explore conceptually related problems

If the linear density of a rod of length L varies as lambda = A+Bx , find the position of its centre of mass .

A thin rod of length L is bent to form a semi circle. The mass of the rod is M . What will be the gravitational potential at the centre of the circle?

A uniform rod of length l is given an impulse at right angles to its length as shown. Find the distance of instantaneous centre of rotation from the centre of the rod. .

A straight rod of length L has one of its end at the origin and the other at X=L . If the mass per unit length of the rod is given by Ax where A is constant, where is its centre of mass?

A thin of length L is bent to form a semicircle. The mass of rod is M. What will be the gravitational potential at the centre of the circle ?

The density of a thin rod of length l varies with the distance x from one end as rho=rho_0(x^2)/(l^2) . Find the position of centre of mass of rod.

A slender homogeneous rod of length 2L floats partly immersed in water, being supported by a string fastened to one of its ends, as shown in the figure. The specific gravity of the rod is 0.36. The length of the rod that extends out of the water is (KL)/(10) Find the value of K.

In example 1.49 find the velocity of the mid point of the rod in terms of its length l, v and theta .

A uniform rod of length L pivoted at the bottom of a pond of depth L//2 stays in stable equilibrium as shown in the figure. Find the force acting at the pivoted end of the rod in terms of mass m of the rod.

A rigid rod of mass m & length l is pivoted at one of its ends. If it is released from its horizontal position, find the speed of the centre of mass of the rod when it becomes vertical.