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A vessel of 100 cm^(2) cross sectional a...

A vessel of `100 cm^(2)` cross sectional area contains water. The mass of water is 2 kg. Find the pressure acting on the bottom surface.

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Mass of water in the vessel = 2 kg
`therefore " Weight" = mg =2kg xx 9.8 m s^(-2)=19.6 N`.
Area of the bottom surface `=100 cm^(2)`
`=1xx10^(-2) m^(2)`
`therefore " Pressure"=("weight")/("area")=(19.6N)/(1xx10^(-2)m^(2))=1960 N m^(-2)=1960 Pa`
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