If the length of the mercury column in a mercury barometer is 76 cm, what is the equivalent height of the water column ?

What is the principle behind a mercury barometer?

If the mercury in the barometer is replaced by water, what will be the resulting height of the water column? Density of water =1000kgm^(-3) density of mercury = 13600kgm^(-3)

Suppose water is used in a barometer instead of mercury. If the barometric pressure is 760 mm Hg , what is the height of the water column in the barometer at 0^(@) C . The densities of water and mercury at 0^(@) C are 0.99987 g cm^(-3) and 13.596 g cm^(-3) , respectively. Strategy : The prtessure exerted by a column of liquid h whose density is d is hdg . Because the pressure are equal , we can equate the expressions for water (W) and mercury (M): h_(W)d_(W)g = h_(M) d_(M)g or h_(W)d_(W) = h_(M)d_(M) Rearranging gives (h_(W))/(h_(M)) = (d_(M))/(d_(W)) This implies that the height of the liquid column in inversely proportional to its density . Solve the equation to find the height of the water column, h_(W) .

If water is used instead of mercury in a barometer, what will be the height of water column?

If the mercury in the barometer is replaced by water what will be the resulting height of the water column? Density of water =1000kgm^(-3) density of mercury =13600 kgm^(-3)

At a given place is barometer records a pressure of 70 cm of mercury. If the mercury in the barometer is replaced by water, what would be the height of the water column? Take density of mercury =13600kg//m^(3) density of water =1000kg//m^(3)