When a metallic sphere is released from the surface of water filled in a container of uniform area of cross section it is found to reach the bottom of the container in 2 s. If the density of the material of the sphere is `4.9 g cm^(-3)`, calculate the pressure exerted by the liquid at the bottom of the container. Assume that only gravitational force and up-thrust act on the body.

Explanation

`(i) V_(0)xx d_(0) xx a= V_(10)xx d_(1)xxg -V_(0)xx d_(1)xx g`
`A=(g(d_(0)-d_(1)))/(d_(0))`
`S=ut+(1)/(2) at^(2)`
P=hdg
(ii) 15,2880 Pa