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A pressure exerted by mercury at the bot...

A pressure exerted by mercury at the bottom of a container of area of cross section `2 cm^(2)` is 10 Pa. Determine the weight of the mercury in the container.

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Pressure `P=("Thrust(weight)")/("Area")`
Thrust =Area `xx` pressure `=2xx10-4xx10=2xx10^(-3)N`
Weight of mercury `=2xx10^(-3) N`.
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