The heat capacity of 80 kg lead is found to be 11.2 kJ `K^(-1)`. Find its specific heat capacity

Explanation

The heat capacity is given by the relation`=mxxs`, where m is the mass of the substance, s is its specific heat capacity.
we are given that, m=80, and heat capacity `=11.2" kJ "K^(-1)`. ltBrgt substituting these values in the equation for heat capacity, we get 11200=`80xxs`
`s=(11200)/(80)=140" J "kg^(-1)" "K^(-1)`
`therefore` The specific heat capacity of lead `=140" J "kg^(-1)" "K^(-1)`.