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Two bodies A and B of equal masses are s...

Two bodies A and B of equal masses are supplied with equal amountt of heat energy. If rise in temperature of A is more than that in B, what is the relation between their specific heats?

Text Solution

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For body A, `Q=mxxs_(A)xxDeltatheta_(A)`
and for body B, `Q=mxxs_(B)xxDeltatheta_(B)`
Dividing (1) by (2), `(S_(A))/(S_(B))=(Deltatheta_(A))/(Deltatheta_(B))`
This shows that specific heat is inversely proportional to rise in temperature, Thus, specific heat of A is less than that of B.
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