Home
Class 8
PHYSICS
Calcualte the mass of stea that should b...

Calcualte the mass of stea that should be passed though 60 g of water at `20^(@)C`, such that the final temperature is `40^(@)C`. (take specific latent heat of steam is 2250 J `g^(-1)`).

Text Solution

Verified by Experts

let mass of stea be m gm
heat given out by stea to form water at `100^(@)C=3xx2250" J "g^(-1)`
heat given out by water at `100^(@)C`
`=ms_(u)Delta theta=mxx4.2xx(100-40)`
`=242" m "J" "g^(-1)`
Total heat given out `=2250m+252m`
`=2502" m J "g^(-1)`
Heat gained by water at `20^(@)C=60xx4.2xx(40-20)`
`=5040J`
`therefore`Heat lost by a body=Heat gained by a body ltBrgt `2502m=5040` ltBrgt `m=(5040)/(2502)=2g`
Promotional Banner

Topper's Solved these Questions

  • HEAT

    PEARSON IIT JEE FOUNDATION|Exercise Very Short Answer Type Question|25 Videos

  • HEAT

    PEARSON IIT JEE FOUNDATION|Exercise Short Answer Type Question|14 Videos

  • FRICTION

    PEARSON IIT JEE FOUNDATION|Exercise Competition Corner |54 Videos

  • HYDROSTATICS

    PEARSON IIT JEE FOUNDATION|Exercise CONCEPT APPLICATION (LEVEL 3)|10 Videos

Similar Questions

Explore conceptually related problems

The amount of steam at 100^@ C that should be passed into 600 g of water at 10^@ C to make the final temperature as 40^@ C will be

Calculate the amount of ice, which is sufficient to cool 45g of water, contained at 30^(@)C , such that the final temperature of the mixture is 10^(@)C . (Take specific latent heat of fusion of ice is 336" J "g^(-1) )

5 g of ice at 0^(@)C is dropped in a beaker containing 20 g of water at 40^(@)C . The final temperature will be

How much steam at 100^(0)C is to be passed into water of mass 100g at 20^(0)C to raise its temperature by 5^(0)C ? (latent heat of steam is 540cal/gm )

Find the heat required to convert 20 g of iceat 0^(@)C into water at the same temperature. ( Specific latent heat of fusion of ice =80 cal//g )