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if specific heat capacity of mercury is 0.033 cal `g^(-1)" ".^(@)C^(-1)`, how much heat is gained by 0.05 kg of mercury when its temperature rises from `68^(@)F` to 313K?

Text Solution

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The initial temperature `=68^(@)F`
`[(5)/(9)(68-32)].^(@)C=20C^(@)`
Final temperature `=313K=(313-273).^(@)C=40^(@)C`
Mass of mercury given `=0.05kg=50g`
Specific heat capacity of mercury =0.033 cal `g^(-1).^(@)C^(-1)
I.e., heat gained by 1 g of mercury for `1^(@)C` rise =0.033 cal
hence, gained by 1 g of mercury for `1^(@)C` rise =0.033`xx50=1.65cal`
`therefore` hear gained by 50 g mercury for `20^(@)C` rise =33 cal
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