In one minute a total charge of 108 C flows through a bulb when it is connected to a cell. Find the electric current flowing through the bulb.

Explanation

We know that electric current is defined as the rate of flow of charge in a circuit.
It is given that the charge flowing through the bulb in 1 minute (= 60 s) is 180 C.
Therefore, the charge that flows in `1s=(180 C)/(60 S)=3 C s^(-1)=3A`
We may use the formula, `I=(Q)/(t)`, where I is the electric current, Q is the charge that flows in t seconds.
Thus, `I=(180C)/(60S)=3 C s^(-1)=3A`
`:.` The electric current flowing in the bulb = 3A.