The length (16 cm) and area of cross section `(4 cm^(2))` of a copper wire are increased by 25% each. If the resistance of original wire is `8 Omega`, find the new resistance.

Explanation

(i)`Rpropl//A`
(ii) ` (R_(1))/(R_(2))=(l_(1))/(l_(2))xx(A_(2))/(A_(1))`
(iii)`l_(2)=l_(1)+0.25l_(2)`
`A_(2)=A_(1)+0.25A_(1)`
(iv)`8 Omega`