Home
Class 6
PHYSICS
Given the volume of air is 1.29 m^(+3). ...

Given the volume of air is `1.29 m^(+3)`. Then express it in c.c.

Text Solution

Verified by Experts

The correct Answer is:
`129 xx 10^(4)` C.C.

Given the volume of air is 1.29 `m^(+3)`
`1.29 m^(3) = 1.29 xx 10^(6) cm^(3) (because 1m = 10^(2) cm)`
`=129 xx 10^(4)` C.C.
Promotional Banner

Topper's Solved these Questions

  • MEASUREMENTS AND MOTION

    PEARSON IIT JEE FOUNDATION|Exercise Test 2|9 Videos
  • MEASUREMENTS AND MOTION

    PEARSON IIT JEE FOUNDATION|Exercise EXAMPLES|32 Videos
  • MEASUREMENTS AND MOTION

    PEARSON IIT JEE FOUNDATION|Exercise concept|5 Videos
  • LIGHT

    PEARSON IIT JEE FOUNDATION|Exercise ASSESSMENT TEST (CROSS WORD )|11 Videos
  • MOVEMENT - AN AMAZING ACTIVITY

    PEARSON IIT JEE FOUNDATION|Exercise CROSSWORD|1 Videos

Similar Questions

Explore conceptually related problems

Given the density of air is 1.29 kg m^(-3) . Then, the relative density of air is ________.

The density of air is 1.293 kg m^3 . Express it in cgs units.

Plane harmonic waves of frequency 500 Hz are produced in air with displacement amplitude of 10mum . Given that density of air is 1.29(kg)/(m^3) and speed of sound in air is 340(m)/(s) . Then

At 10^5 Nm^(-2) atmospheric pressure the density of air is 1.29 kg m^(-3) .If gamma=1.41 for air, calculate the speed of sound in air.

Calculate the value of mechanical equivalent of heat from the following data. Specific heat capcity of air at constant volume = 170 cal kg^(-1) K^(-1) , gamma = C_p/ C_v = 1.4 and the density of air at STP is 1.29 kg m^(-3) . Gas constant R = 8.3 JK^(-1) mol^(-1) .