Let f(x) `underset( 2X -3 " "1 lt X lt 3)(={ -X^(2) +((b^(3) -b^(2) +b-1))/((b^(2) +3b+2))}} 0le X lt1`
Find al possible values of b such that f(x) has the smallest values at x=1

let f(x)=-x^(3)+(b^(3)-b^(2)+b-1)/(b^(2)+3b+2) if x is 0 to 1 and f(x)=2x-3 if x if 1 to 3. All possible real values of b such that f(x) has the smallest value at x=1 are

let f(x)=-x^3+(b^3-b^2+b-1)/(b^2+3b+2) if x is 0 to 1 and f(x)=2x-3 if x if 1 to 3 .All possible real values of b such that f (x) has the smallest value at x=1 ,are

let f(x)=-x^3+(b^3-b^2+b-1)/(b^2+3b+2) if x is 0 to 1 and f(x)=2x-3 if x if 1 to 3 .All possible real values of b such that f (x) has the smallest value at x=1 are

let f(x)=-x^3+(b^3-b^2+b-1)/(b^2+3b+2) if x is 0 to 1 and f(x)=2x-3 if x is 1 to 3 .All possible real values of b such that f (x) has the smallest value at x=1 are

Let f(x) ={underset(x^(2) +xb " " x ge1)(3-x " "0le x lt1). Find the set of values of b such that f(x) has a local minima at x=1.

Let f(x) ={underset(x^(2) +xb " " x ge1)(3-x " "0le x lt1). Find the set of values of b such that f(x) has a local minima at x=1.

Let f(x)={{:(3x^2-2x+10, x lt 1),(-2,x gt 1):} The set of values of b for which f(x) has greatest value at x=1 is

The function f(x) = (x^(2))/(a) , if 0 le x le 1 =a, if 1 le x lt sqrt(2) = (2b^(2) - 4b)/(x^(2)) , if sqrt(2) le x lt oo is continuous for 0 le x lt oo , then the most suitable values for a and b are :