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- sin36^@sin72^@sin108^@sin144^@=5/16
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- Prove that: sin36^0=(sqrt(10-2sqrt(5)))/4 .
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- sin36^(@)sin72^(@)sin108^(@)sin144^(@)=(5)/(16)
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- sin36^(@)sin72^(@)sin108^(@)sin144^(@)=
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- sin36^(@)sin72^(@)sin108^(@)sin144^(@)=
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- Find the Value of cos 18^@ or sin 72^@
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- Prove that: sin36^0s in 72^0s in 108^0s in 144^0=5/(16)dot
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- Find the value of (cos18^(@))/(sin72^@)
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- The values of sin72^(@)andcos108^(@) are equal.
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