Force acting on a particale is `(2hat(i)+3hat(j))N`. Work done by this force is zero, when the particle is moved on the line `3y+kx=5`. Here value of k is `(`Work done `W=vec(F).vec(d))`

Force acting on a particle is (2hati+3hatj) N. Work done by this force is zero ,when a particle is moved on the line 3y+kx=5 . Here value of k is

Force acting on a particle is (2hati+3hatj)N . Work done by the force is zero, when a particle is moved along the line 3y+kx=5 . Here the value of k is

A force bar F = (3hat i-4 hat j +b hat k)N is acting on the particle which is moving from point A ( 0-1, 1) m to the point B(2, 2 3) m If net work done by the force on the particle is zero then value of b is

If vec(F) = y hat(i) + x hat(j) then find out the work done in moving the particle from position (2,3) to (5,6)

A force (3 hat(i)+4 hat(j)) acts on a body and displaces it by (3 hat(i)+4 hat(j))m . The work done by the force is