Home
Class 12
BIOLOGY
CO(2)+H(2)O hArr H(2)CO(3) In the abse...

`CO_(2)+H_(2)O hArr H_(2)CO_(3)`
In the absence of an enzyme, the above reaction is :

A

Very slow and about 2000 molecules of product are formed per minute

B

Very slow and about 200 molecules of products are formed per minute

C

Very slow and about 200 molecules of products are formed per hour

D

Very fast, and about 6,00,000 molecules of products are formed per second.

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Similar Questions

Explore conceptually related problems

CO_2+ H_2O harr H_2CO_3 . In the absence of an enzyme, this above reaction is

CO_2+ H_2O leftrightarrow H_2CO_3 In the absence of an enzyme, this above reaction is

Study the reaction given below CO_(2)+H_(2)O underset("EnZyme")hArr H_(2)CO_(3) In absence of any enzyme this reaction is very slow, with 200 molecules of H_(2)CO_(3) being formed in an hour. In presence of enzyme the reaction speeds up dramatically with about 6000,000 molecules formed every second. Name the enzyme which has accelerated up the reaction by 10 million times.

underline(C)O_(2)+H_(2)O to H_(2)CO_(3)

underset("Sucrose")(C_(12)H_(22)O_(11)+H_(2)O) overset("Enzyme A")tounderset("Glucose")(C_(6)H_(12)O_(6))+underset("Fructose")(C_(6)H_(12)O_(6)) underset("Glucose")(C_(6)H_(12)O_(6)) overset("Enzyme B")to2C_(2)H_(5)OH+2CO_(2) In the above reactions, the enzyme A and enzyme B respectively are :

The equilibrium constant for the reaction is H_(2)O_((l))+CO_((g)) Leftrightarrow H_(2(g))+CO_(2(g)) is 64. If the rate constant for the forward reaction is 160, the rate constant for the backward reaction is

For the following reactions (1) , (2) and (3) equilibrium constants are given (1) CO_(2)(g) +H_(2)O(g) hArr CO_(2)(g) +H_(2)(g), K_(1) (2) CH_(4)(g) +H_(2)O(g) hArr CO(g)+3H_(2)(g),K_(2) (3) CH_(4)(g)+2H_(2)O(g) hArr CO_(2)(g)+4H_(2)(g), K_(3) Which of the following relation is correct ?

In the reaction HNO_(3)+H_(2)O hArr H_(2)O ^(+) +NO_(3)^(-) the conjugate base of HNO_(3) is