Fixed volume of `0.1M` benzoic acid `(pK_(a) = 4.2)` solution is added into `0.2M` sodium benzote solution and formed a `300mL`, resulting acidic buffer solution. If `pH` of the resulting solution is `3.9`, then added volume of banzoic acid is

Fixed volume of 0.1 M benzoic acid (pK_(a)=4.2) solution is added into 0.2 M sodium benzoate solution and formed a 300 mL, resultant acidic buffer solution. If pH of this buffer solution is 4.5 then find added volume of benzoic acid :

Fixed volume of 0.1 M benzoic acid (pK_(a)=4.2) solution is added into 0.2 M sodium benzoate solution and formed a 300 mL, resultant acidic buffer solution. If pH of this buffer solution is 4.5 then find added volume of benzoic acid :

Fixed volume of 0.1 M benzoic acid (pK_(a)=4.2) solution is added into 0.2 M sodium benzoate solution and formed a 300 mL, resultant acidic buffer solution. If pH of this buffer solution is 4.5 then find added volume of benzoic acid :

Fixed volume of 0.1M benzoic acid solution is added into 0.2 M soldium benzoate solution and formed a 300 ml, resultant acidic buffer solution. If pH of this buffer solution is 4.5 then find added volume of benzoic acid - (Given : pK_(a) benzoic acid =4.2)

20 mL 0.1 (N) acetic acid is mixed with 10 mL 0.1(N) NaOH solution. pH of the resulting solution is ( pK_(a) of acetic acid is 4.74)-

On millilitre solution of 0.01 M HCl is added to 1L of sodium chloride solution. What will be the pH of the resulting solution ?

1 M benzoic acid (pK_a=4.20) and 1 M C_6H_5COONa solutions are given separately What is the volume of benzoic acid required to prepare a 300 ml buffer solution of pH =4.5 ? [log 2 =0.3]

Calculate the volume of 0.1 M acetic acid solution to be mixed with 50cm^(3) of 0.2M sodium acetate solution, in order to prepare a standard buffer of pH 4.94 ( pK_(a) of acetic acid = 4.74).