Rolle's theorem is not applicable to the function `f(x)=|x|"for"-2 le x le2` becase

Rolle's theorem is not applicable to the function f(x)=|x|"for"-2 le x le2 because

Rolle's theorem is not applicable to the function f (x) = |x| for -2 le x le 2 becaue

Rolle's theorem is not applicable to the function f(x)=|x| for -2lexle2 because

Rolle's theorem is applicable for the function f(x) = |x-1| in [0,2] .

Rolle's theorem is applicable for the function f(x) = |x-1| in [0,2] .

Rolle's theorem is applicable for the function f(x) = |x-1| "in " x in [0, 2]

Examine whether Rolle's theorem is applicable to the function f(x) = cot x in -pi/2le x le pi/2

Fill in the blanks: Rolle's Theorem is not applicable to the function f(x) = (x-1)^(2//3) on [0,2] as f is not derivable at ………… .

State Rolle's theorem. Is this theorem applicable to the function f(x)=x in the interval -1 le x le 1 ?

Rolle's theorem is not applicable to f(x) = |x| in [ -2,2] because