let `f(x)=[tan(pi/4+x)]^(1/x) , x!=0` and `f(x)=k , x=0` then the value of `k` such that `f(x)` hold continuity at `x=0`

f(x)=[tan(pi/4+x)]^(1/x), x!=0 and f(x)=k, x=0 is continuous at x=0 then k=

Let f (x) = { tan "" ((pi)/(4) + x)}^(1/x) , x ne 0 " and " f(0) = k . For what value of k, f(x) is

f(x) = {{:(("tan"((pi)/(4)+x))^(1//x)",",x ne 0),(k",",x = 0):} for what value of k, f(x) is continuous at x = 0 ?

f(x) = {{:(("tan"((pi)/(4)+x))^(1//x)",",x ne 0),(k",",x = 0):} for what value of k, f(x) is continuous at x = 0 ?

f(x) = {{:(("tan"((pi)/(4)+x))^(1//x)",",x ne 0),(k",",x = 0):} for what value of k, f(x) is continuous at x = 0 ?

The value of f(0) so that f(x)=(3x+4 tan x)/(x) is continuous at x=0 is

If f(x)={{:(,x([(1)/(x)]+[(2)/(x)]+.....+[(n)/(x)]),x ne 0),(,k,x=0):} and n in N . Then the value of k for which f(x) is continuous at x=0 is

If f(x)={{:(,x([(1)/(x)]+[(2)/(x)]+.....+[(n)/(x)]),x ne 0),(,k,x=0):} and n in N . Then the value of k for which f(x) is continuous at x=0 is