An electric motor raises a load of 0.2 kg, at a constant speed, through a vertical distance of 3.0 m in 2 s. If the acceleration of free fall is `10 m//s^(2)`, the power in W developed by the motor in raising the load is :

An electric motor creates a tension of 4500 newton in a hoisting cable and reels it at the rate of 2 m//s . What is the power of the motor ?

A coolie 1.5 m tall raises a load of 80 kg in 2 sec from the ground to his head and then walks a distance of 40 m in another 2 second. The power developed by the coolie is : (g = 10 m//s^(2))

A coolie 1.5 m tall raises a load of 80 kg in 2 sec from the ground to his head and then walks a distance of 40 m in another 2 second. The power developed by the coolie is : (g = 10 m//s^(2))

(b) A 10 kg weight is raised to a height of 2.0 m with an acceleration of 1.5 m//s^(2) . Compute the work done, if g=10 m//s^(2) .

An elevator which can carry a maximum load of 1800kg is moving with a constant speed of 2ms^(-1) . The frictional force opposing the motino is 5000N . Calculate the minimum power delivered by the motor to the elevator in watt and hp ? Take g=10m//s^(2)