An alcohol (x) gives blue colorin Victormayer's test and 3.7g of X when treated with metallic sodium liberates 560 mL of hydrogen at 273 K and 1 atm pressure what will be the possible structure of X?

Options

A. `CH_(3)CH(OH)CH_(2)CH_(3)`
B. `CH_(3)-CH(OH)-CH_(3)`
C. `CH_(3)-C(OH)-(CH_(3))_(2)`
D. `CH_(3)-CH_(2)-CH(OH)-CH_(2)-CH_(3)`

Answer

A

Explanation

`2R-OH+Nato2RONa+2H_(2)uarr` 2 moles of alcohol gives 1 mole of `H_(2)` which occupies 22.4 L at 273 K and 1 atm
`therefore` number of moles of alcohol = `(2"moles of "R-OH)/(22.4L" of "H_(2))xx560mL=0.05`moles
`therefore` number of moles = `"mass"/("molar mass")rArr"molar mass"=3.7/0.05=74gmol^(-1)`
General formula for `R-OHC_(n)H_(2n+1)-OH`
`thereforen(12)+(2n+1)(1)+16+1=74`
14n = 74 - 18
14n = 56
`thereforen=56/4=4`
The `2^(@)` alcohol which contains 4 carbon is `CH_(3)CH(OH)CH_(2)CH_(3)`