The percentage of pyridine `(C_5H_5N)` that forms pyridinium ion `(C_5H_5NH)` in a 0.10 M aqueous pyridine solution `(K_b` for `C_5H_5N=1.7 times 10^-9`) is………..

Options

A. `0.006%`
B. `0.013%`
C. `0.77%`
D. `1.6%`

Explanation

`C_5H_5N+H-OH leftrightarrowC_5H_5NH+OH^(-)`
`(a^2C)/(1-a)=K_b`
`a^2C approxK_b`
`a=sqrt((K_b)/C)sqrt((1.7 times 10^-9)/(0.1))=sqrt1.7 times 10^-4`
Percentage of dissociation
`sqrt1.7 times 10^-4 times 100=1.3 times 10^-2=0.013%`