[mu=A+(B)/(lambda^(2))],[mu rarr" ref ruchive index "],[lambda-" wavelength "],[" calculate simensions "8" A and "B]

The refractive index of a medium is given by mu=A+(B)/(lambda^(2)) where A and B are constants and lambda is the wavelength of light. Then the dimensions of B are the same as that of

Refractive index mu is given as mu=A+B/lambda^2, where A and B are constants and lambda is wavelength, then dimensions of B are same as that of

Refractive index mu is given as mu=A+B/lambda^2, where A and B are constants and lambda is wavelength, then dimensions of B are same as that of

Refractive index mu is given as mu=A+B/lambda^2, where A and B are constants and lambda is wavelength, then dimensions of B are same as that of

Refractive index mu is given as mu=A+B/lambda^2, where A and B are constants and lambda is wavelength, then dimensions of B are same as that of

The correct curve between refractive index mu and wavelength lambda will be

The correct curve between refractive index mu and wavelength lambda will be

The refractive index ( mu ) of glass is related to the wavelength (lambda) of incident light as mu = A +(B)/(lambda^(2)) , where A and B are constants. Find out the dimensions of A and B.

The relation between refractive index and the wavelength light mu= A + B//lambda^2 . What is the dimension of B?