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The DeltaH(f)^(0)N(2)O(5(g)) in KJ/mol o...

The `DeltaH_(f)^(0)N_(2)O_(5(g))` in KJ/mol on the basis of the following data is
`2NO_((g))+O_(2(g))rarr2NO_(2(g))DeltaH_(f)^(0)=-114KJmol^(-1)`
`NO_(2)+O_(2(g))rarr2N_(2)O_(5(g))`
`Delta_(f)H^(0)NO_((g))=90.2KJmol^(-1)`

Text Solution

Verified by Experts

`(1)/(2)N_(2(g))+(1)/(2)O_(2(g))rarrNO_((g))Delta_(f)H^(0)=90.2`
`N_((g))+O_(2(g))rarr2NO_((g))Delta_(f)H^(0)=90.2xx2rarr(1)`
`NO_((g))+O_(2(g))rarr2NO_(2(g))Delta_(f)H^(0)=-14rarr(2)`
`2NO_(2(g))+(1)/(2)O_(2(g))rarrN_(2)O_(5(g))`
`Delta_(f)H^(0)=(-102.6)/(2)=-51.3rarr(3)`
From equations `(1)+(2)+(3)`
`N_(2(g))+(5)/(2)O_(2(g))rarrN_(2)O_(5(g))`
`Delta_(f)H^(0)N_(2)O_(5(g))=15.1KJmol^(-1)`
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