Calculate the bond enthalpy of HCl. Given that the bond enthalpies of `H_(2)` and `Cl_(2)` are `430KJmol^(-1) and 242KJmol^(-1)` respectively and `Delta_(f)H^(0)HCl` is `-91KJmol^(-1)`)

Explanation

To calculate the bond enthalpy of HCl, we can use the following thermodynamic relationship based on the formation of HCl from its elements:

1. **Write the balanced chemical equation for the formation of HCl:**
\[ \text{H}_2(g) + \frac{1}{2} \text{Cl}_2(g) \rightarrow \text{HCl}(g) \]

2. **Identify the given bond enthalpies and the standard enthalpy of formation:**
...