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Given that bond energies of N=N,H-H and ...

Given that bond energies of N=N,H-H and N-H bonds as 945, 436 and 391 kJ/ mol respectively ,the enthalpy of the reaction `N_(2)(g)+3H_(2)(g)+to2NH_(3)(g),`is

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We need `N_(2)+3H_(2)rarr2NH_(3)`
`Delta_(r)H=?`
`N-=N+3H-Hrarr2underset(H)underset(|)overset(H)overset(|)(N)-H Delta_(r)H=?`
`N-=N+3H-Hrarr6N-H`
`Delta_(r )H=?`
`Delta_(r)H=sumBE` of reactants - `sum BE` of products
`=B.E_(N-=N)+2B.E_(H-H)-6B.E_(N-H)`
`=945+3xx436-6(391)=-93KJ`
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