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Determine enthalpy change for the reacti...

Determine enthalpy change for the reaction,
`CH_(4(g))+Cl_(2(g))rarr CH_(3)Cl_((g))+HCl_((g))`
Bond energies for `C-H,C-Cl,Cl-Cl,H-Cl` are `412,338,242,431k J mol^(-1)` respectively.

Text Solution

Verified by Experts

`Delta_(r )H^(0)` = [Total energy used dissociation of bonds] - [Total energy used in formation of bonds]
`=[4B.E_(C-H)+B.E_(Cl-Cl)]-[3BE_(C-H)+B.E_(C-Cl)+B.E_(H-Cl)]`
`=[4(412)+1(242)]-[3(412)+1(338)+1(431)]`
`=[1890]-[2005]`
`=-115KJmol^(-1)`
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